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(1/8)^x=32
We move all terms to the left:
(1/8)^x-(32)=0
Domain of the equation: 8)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/8)^x-32=0
We multiply all the terms by the denominator
(+1-32*8)^x=0
We add all the numbers together, and all the variables
(-255)^x=0
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